QuickDBS.MySQL 1.0.3.4

MySql example

Open or Create and Open MySql connection to the database. If the database needs to be created and no absolute path is provided, it will create in the same folder as the executable file is.

var db = new QuickDBS.MySQL("complete connection string"); // This is with connection string
var db = new QuickDBS.MySQL("dbname", "rootpassword", true); // This with database, password and to create a new database if not exists.

Create a table from a Person class. The result will be true if created and false if failed or not-created.

public class Person
{
    public Int64 Id { get; set; }
    public string Name { get; set; }
    public double Income { get; set; }
    public DateTime DateOfBirth { get; set; }
}

var result = db.CreateTable<Person>();

Create a Person record in the Person table create above. The result will be the last insert Id of the table which will be unique.

var id = db.Create<Person>(new Person {
  Name = "Rahul",
  Income = 5000,
  DateOfBirth = new DateTime(2000, 01, 01)
});

Get the person record having Id = 1 from the Person table.

var person = db.GetById<Person>(1);
person.Name = "Rahul Hadgal";
person.Income = 10000;

Update the income for person selected in the above example, from 5000 to 10000 and change name to Full Name.

var result = db.UpdateById<Person>(person);

Get all records from Person table

var people = db.GetAll<Person>();

Custom Query with conditions

var people = db.Query<dynamic>("SELECT Id, Name, Income FROM Person WHERE
                                Income >= @MinIncome AND Income <= @MaxIncome",
                                new { MinIncome = 6000, MaxIncome = 12000 });

Delete a person by Id = 1 from the Person table

var result = db.DeleteById<Person>(1);