ObjectGenerator.NET 1.0.1.3

Generates Strongly Typed Objects from valid JSON without using reflection

Examples/Tests

You can see multiple working examples by looking at the Tests

Generating An Object

An object can be generated by using an ObjectGenerator and providing it with Type Information and a method to create New Objects

Below is a full example of a List<Testable> object being created from JSON

static Func<Testable> NewObjectTestable = () => new Testable();

static Func<TestableArray> NewObject = () => new TestableArray();

string doubleTestData = "[" +
    "{" +
    "\"testInt\":1234567890," +
    "\"testString\":\"The quick brown fox, jumps over; the lazy dog.\"," +
    "\"testDecimal\":\"1234.000000\"," +
    "\"testLong\":234556667777788888," +
    "\"testBoolean\":true," +
    "\"testArray\":[[\"BTC1\",\"701.90000000\",\"713.90000000\"],[\"BTC2\",\"702.90000000\",\"723.90000000\"]]," +
    "\"testObject\":{[\"BTC1\",\"701.90000000\",\"713.90000000\"],[\"BTC2\",\"702.90000000\",\"723.90000000\"]}," +
    "}," +
    "{" +
    "\"testInt\":1234567890," +
    "\"testString\":\"The quick brown fox, jumps over; the lazy dog.\"," +
    "\"testDecimal\":\"1234.000000\"," +
    "\"testLong\":234556667777788888," +
    "\"testBoolean\":true," +
    "\"testArray\":[[\"BTC1\",\"701.90000000\",\"713.90000000\"],[\"BTC2\",\"702.90000000\",\"723.90000000\"]]," +
    "\"testObject\":{[\"BTC1\",\"701.90000000\",\"713.90000000\"],[\"BTC2\",\"702.90000000\",\"723.90000000\"]}," +
    "}" +
    "]";

List<Testable> doubleTest = new List<Testable>();

ObjectGenerator<Testable>.GenerateEnumerable(ref NewObjectTestable, ref doubleTest, ref doubleTestData, TestableTypeInformation);

Providing New Objects

When using a Generator you will need to provide a method to create a new object

This can be as simple as the examples below or any method that returns the correct type and matches the signature

static Func<Testable> NewObjectTestable = () => new Testable();

static Func<TestableArray> NewObject = () => new TestableArray();

Creating a Generator

To generate an object you need to provide information about the type and how the members will be generated

These can have references to other Generators

public static void TestableTypeInformation(Testable obj, string valueName, string value)
{
    switch (valueName)
    {
        case "testInt":
            {
                obj.TestInt = int.Parse(value);

                break;
            }
        case "testString":
            {
                obj.TestString = value.Trim('"');

                break;
            }
        case "testDecimal":
            {
                obj.TestDecimal = decimal.Parse(value.Trim('"'));

                break;
            }
        case "testBoolean":
            {
                obj.TestBoolean = bool.Parse(value);

                break;
            }
        case "testLong":
            {
                obj.TestLong = long.Parse(value);

                break;
            }
        case "testArray":
            {
                List<TestableArray> array = new List<TestableArray>();

                ObjectGenerator<TestableArray>.GenerateEnumerableArray(ref NewObject, ref array, ref value, ArrayTypeInformation);

                obj.TestArray = array;

                break;
            }
        case "testObject":
            {
                List<TestableArray> array = new List<TestableArray>();

                ObjectGenerator<TestableArray>.GenerateEnumerableArray(ref NewObject, ref array, ref value, ArrayTypeInformation);

                obj.TestObject = array;

                break;
            }
    }
}

Array types need their information provided a different way, the members should be in the expected order

public static void ArrayTypeInformation(TestableArray obj, int position, string value)
{
    switch (position)
    {
        case 0:
            {
                obj.Symbol = value.Trim('"');

                break;
            }
        case 1:
            {
                obj.Price = decimal.Parse(value.Trim('"'));

                break;
            }
        case 2:
            {
                obj.Price2 = decimal.Parse(value.Trim('"'));

                break;
            }
    }
}